The distances of a point 'P' from the points `A(5,-4),B(7,6)` are in the ratio `2:3` and the locus of P is `x^(2)+y^(2)-(34)/(5)x+(120)/(5)y+k=0` then "k" is

If the distance from P to the points (5,-4),(7,6) are in the ratio 2:3, then the locus of P is

If the distance from P to the points (5,-4),(7,6) are in the ratio 2:3, then the locus of P is

If the distances from P to the points (5,–4), (7, 6) are in the ratio 2 : 3, then find the locus of P

If the distance from P to the points (5,-4) (7,6) are in the ratio 2 :3 , then find the locus of P.

If the distance from P to the points (5,-4) (7,6) are in the ratio 2 :3 , then find the locus of P.

If the distances from P to the points (5,-4),(7,6) are in the ratio 2:3, then find the locus

If the distance from P to the points (3,4) and (-3,4) are in the ratio 3:2, find the locus of P.

If the distance from P to the points (5,-4),(7,6) are in the ratio 2:3 ,then the locus of P is 5x^(2)+5y^(2)-12x-86y+17=0 , 5x^(2)+5y^(2)-34x+120y+29=0, 5x^(2)+5y^(2)-5x+y+14=0 3x^(2)+3y^(2)-20x+38y+87=0

The distance of point P(x, y) from the points A(1, -3) and B(-2, 2) are in the ratio 2 : 3. Show that 5x^(2) + 5y^(2) - 34x + 70y + 58 = 0 .