Natural length of a spring is 60 cm, and its spring constant is 4000 N/m, A mass of 20 kg is hung from it. The extension produced in the spring is (take `g=9.8m//s^(2)`)

Natural length of a spring is 60 cm and its spring constant is 4000 N/m. A mass of 20 kg is hung from it. The extension produced in the spring is (Take, g = 9.8 m//s^(2) )

Natural length of a spring is 60 cm and its spring constant is 4000 N/m. A mass of 20 kg is hung from it. The extension produced in the spring is (Take, g = 9.8 m//s^(2) )

In spring constant of the spring is 100 N//m Extension produced in the spring is: (g=10 m//s^(2))

A block of mass 20 kg is hung with the help of ideal string, pulleys and spring (Spring constant k = 1000 N/m) as shown in figure. If block is in equilibrium position then extension in the spring will be (g = 10 ms^-2)

A spring has natural length 40 cm and spring constant 500 N//m . A block of mass 1 kg is attached at one end of the spring and other end of the spring is attached to a ceiling. The block is relesed from the position, where the spring has length 45 cm .

A spring has natural length 40 cm and spring constant 500 N//m . A block of mass 1 kg is attached at one end of the spring and other end of the spring is attached to a ceiling. The block is relesed from the position, where the spring has length 45 cm .

The time period of an oscillating spring of mass 630 g and spring constant 100 N/m with a load of 1 kg is

Force constant of a spring is 100 N//m . If a 10kg block attached with the spring is at rest, then find extension in the spring. ( g= 10 m//s^(2) )

A block of mass m = 2.0 kg is dropped from height h = 40 cm onto a spring of spring constant k = 1960 N//s . Find the maximum distance through which the spring is compressed. Take g = 9.8 m//s^(2)