Consider two arbitaray decay equation and mark the correct alternative` s` given below. (i) `._(92)^(230)U rarr n+._(92)^(229)U` (ii)`._(92_^(230)U rarr P +._(91)^(229)Pa`
Given: `M(._(92)^(230)U) =230.033927 u,M(._(92)^(229)U)=229.03349 u, m_(n)=1.008665u`, `M(._(91)^(229)Pa) =229.032089, m_p`=1.007825, 1 am u =931.5 MeV`.

Show that ._(92)^(230)U does not decay by emitting a neutron or proton. Given: M(._(92)^(230)U)=230.033927 am u, M(._(92)^(230)U)=229.033496 am u , M(._(92)^(229)Pa)=229.032089 am u, M(n)=1.008665 am u m(p)=1.007825 am u .

Show that ._(92)^(230)U does not decay by emitting a neutron or proton. Given: M(._(92)^(230)U)=230.033927 am u, M(._(92)^(230)U)=229.033496 am u , M(._(92)^(229)Pa)=229.032089 am u, M(n)=1.008665 am u m(p)=1.007825 am u .

The partlcles emitted 1n the decay of ""_(92)^(238)U to ""_(92)^(234)U

U_(92)^298 + n_(0)^1 to U_(92)^(238) + ______ .

""_(91)^(234)Pa rarr ""_(92)^(234)U occurs with the emission of

Consider the following nuclear decay: (initially .^(236)U_(92) is at rest) ._(92)^(236)rarr._(90)^(232)ThrarrX Following atomic masses and conversion factor are provided ._(92)^(236)U=236.045 562 u , ._(90)^(232)Th=232.038054 u , ._(0)^(1)n=1.008665 ,. _(1)^(1)p=1.007277 u , ._(2)^(4)He=4.002603 u and 1 u=1.5xx10^(-10)J The amount of energy released in this decay is equal to:

Consider the following nuclear decay: (initially .^(236)U_(92) is at rest) ._(92)^(236)rarr._(90)^(232)ThrarrX Following atomic masses and conversion factor are provided ._(92)^(236)U=236.045 562 u , ._(90)^(232)Th=232.038054 u , ._(0)^(1)n=1.008665 ,. _(1)^(1)p=1.007277 u , ._(2)^(4)He=4.002603 u and 1 u=1.5xx10^(-10)J The amount of energy released in this decay is equal to: