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Show that the bisectors of angles of a ...

Show that the bisectors of angles of a parallelogram form a rectangle.

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The bisectors of angles of a parallelogram from a :

Show that the angle bisectors of a parallelogram form a rectangle.

Prove that the quadrilateral formed by the bisectors of the angles of a parallelogram is a rectangle.

Prove that the quadrilateral formed by the bisectors of the angles of a parallelogram is a rectangle.

Prove that the quadrilateral formed by the bisectors of the angles of a parallelogram is a rectangle.

The angle bisectors of a parallelogram form a rectangle.

The angle bisectors of a parallelogram form a rectangle.

The angle bisectors of a parallelogram form a rectangle.

In the alongside diagram, the bisectors of interior angles of the parallelogram PQRS enclose a quadrilateral ABCD. Show that: (i) anglePSB+angleSPB=90^(@) (ii) anglePBS=90^(@) (iii) angleABC=90^(@) (iv) angleADC=90^(@) (v) angleA=90^(@) (vi) ABCD is a rectangle thus, the bisectors of the angles of a parallelogram enclose a rectangle.

Shape made by the bisectors of angles of a parallelogram is