`A_(3)(g)hArr 3A(g)`, In the above reaction, the initial conc. Of `A_(3)` is 'a' moles/lit. If x is degree of dissociation of `A_(3)`. The total number of moles at equilibrium will be

If in the reaction, N_(2)O_(4)(g)hArr2NO_(2)(g), alpha is the degree of dissociation of N_(2)O_(4) , then the number of moles at equilibrium will be

If in the reaction, N_(2)O_(4)(g)hArr2NO_(2)(g), alpha is the degree of dissociation of N_(2)O_(4) , then the number of moles at equilibrium will be

In a reaction PCI_(5)hArrPCI_(3) + CI_(2) degree of dissociation is 30% . If initial moles of PCI_(3) is one then total moles at equilibrium is

1.2 moles of SO_(3) are allowed to dissociate in a 2 litre vessel the reaction is 2SO_(3(g)) hArr 2SO_(2(g)) +O_(2(g)) and the concent ration of oxygen at equilibrium is 0.1 mole per litre. The total number of moles at equilibrium will be

3 moles of NH_3 are allowed to dissociate in a 5 litre vessel and the equilibrium concentration of N_2 is 0.2 mole/lit . Then the total number of moles at equilibrium is

For reaction 2NO(g)hArr N_(2)(g)+O_(2)(g) degree of dissociation of N_(2) and O_(2) is x. Initially 1 mole of NO is taken then number of moles of O_(2) at equilibrium is

For reaction 2NO(g)hArr N_(2)(g)+O_(2)(g) degree of dissociation of N_(2) and O_(2) is x. Initially 1 mole of NO is taken then number of moles of O_(2) at equilibrium is

In the following reaction started only with A_(8), 2A_(8)(g) hArr3A_(2)(g)+A_(4)(g) mole fraction of A_(2) is found to 0.36 at a total pressure of 100 atm at equilibrium. The mole fraction of A_(8)(g) at equlibrium is :

In the following reaction started only with A_(B), 2A_(B)(g) hArr3A_(2)(g)+A_(4)(g) mole fraction of A_(2) is found to 0.36 at a total pressure of 100 atm at equilibrium. The mole fraction of A_(8)(g) at equlibrium is :

2 is the equilibrium constant for the reaction A_(2)+B_(2)hArr 2AB at a given temperature. What is the degree of dissociation for A_(2)" or "B_(2)