A circular coil of radius R having N number of turns carries a steady current I. The matnetic induction at the centre of the coil is 0.1 tesla. If the number of turns is doubled and the radius is halved, wyhich one of the following will be the correct value for the magnetic induction at the centre of the coil?

A circular coil of radius 'r' having N turns carries a current ''I''. What is its magnetic moment ?

A circular coil of radius r having number of turns n and carrying a current A produces magnetic induction at its centre of magnitude B. B can be doubled by

A circular coil of radius r having number of turns n and carrying a current A produces magnetic induction at its centre of magnitude B. B can be doubled by

A circular coil of n turns and radius r carries a current I. The magnetic field at the centre is

A circular coil of radius 'r' having 'n' turns carries a current 'I' . The magnetic induction at the center of the coil is 'B' . Now the coil is unwound and rewound with half the original radius. If the magnetic induction at the center of the coil is to be the same, the current that should be passed through the coil is

A circular coil of wire of radius 'r' has 'n' turns and carries a current 'I'. The magnetic induction (B) at a point on the axis of the coil at a distance sqrt3r from its centre is

A circular coil of 5 cm radius, number of turns 100 carries a current of 2A. Calculate the magnetic field (a) At the centre of the coil (b) At a distance 10cm from the centre along the axis of the coil

The radius and number of turns of a circular coil are doubled. The magnetic intensity at its centre will be