If H(2)+1//2O(2)rarr H(2)O , Delta =-68....

If `H_(2)+1//2O_(2)rarr H_(2)O , Delta =-68.39` Kcal
`K+H_(2)O+ "water" rarr KOH(aq)+1//2H_(2) , Delta H=-48.0` Kcal
`KOH+"water" rarr KOH(aq)Delta H=-14.0` Kcal the heat of formation of KOH is -

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