Fine `bar( u)` , if `Sigma f_(i) u_(i ) 252` and `Sigmaf_(i) = 420`

Find the value of the mean barX , " if " Sigma f_(i) x_(i) = 30 " and " Sigma f_(i) = 6 .

The mean of the data by step deviation method is 1896 . Find the value of g, if Sigma f_(i) u_(i) = 66, Sigma f_(i) = 100" and " A = 1500 .

Find the value of bar u for the following information : (i) A = 22.5 , x_(i) = 27.5 , g = 5 " "(ii) Sigma f_(i)u_(i) = 54 , Sigma f_(i) = 120

Find barX by step deviation method : Given : A = 2200. " "Sigma f_(i)u_(i) = - 15, " "Sigma f_(i) = 100 " and " g = 400 .

The mean of the data by step deviation method is Rs. 1390. Find the assumed mean (A), if Sigma f_(i) = 50, Sigma f_(i) u_(i) = 28 " and " g = 250 .

Mean of a frequency distribution (bar(x)) " is " 45 . If Sigma f_(i) = 20 " find " Sigma f_(i) x_(i)

If u_i = (x_1 -25)/10, Sigma f_i u_i = 20 and Sigma f_i = 100 , then find the value of bar x .

Find the value of Sigmaf_(i) d_(i) for the following information. (i) bard = 1.2 , Sigmaf_(i) = 15 " "(ii) bar d = 1.75, Sigmaf_(i) = 80

If u_(i)=(x_(i)-15)/(8), Sigma f_(i)u_(i)=20, and Sigmaf_(i)=80, barx is

Find the correct answer from the alternative given : The formula to find mean from a grouped frequency table is barX = A + (Sigma f_(i)u_(i))/(Sigmaf_(i))xxg In the formula , u_(i) = ….