The value of the determinant `|{:(m,n,p),(p,m,n),(n,p,m):}|`

The value of the determinant det[[m,n,pp,m,nn,p,m]] is

If the sum of m terms of an A.P is equal to these that n terms and also to the sum of the next p terms,prove (m+n)((1)/(m)-(1)/(p))=(m+p)((1)/(m)-(1)/(n))

If the sum of the first m terms of an A.P. is equal to the sum of either the next n terms or the next p terms, prove that, (m+n)((1)/(m)-(1)/(p)) = (m+p)((1)/(m) - (1)/(n))

If the sum of m terms of an A.P.is equal to the sum of either the next n terms or the next p terms,then prove that (m+n)((1)/(m)-(1)/(p))=(m+p)((1)/(m)-(1)/(n))

The common ratio of the G.P. a^(m-n), a^(m), a^(m+n) is ……………

Find the value of sum_(p=1)^(n)(sum_(m=p)^(n)C_(m)^(m)C_(p)) And hence,find the value of lim_(n rarr oo)(1)/(3^(n))sum_(p=1)^(n)(sum_(m=p)^(n)C_(m)^(m)C_(p))

If the sum of m terms of an A.P. is equal to the sum of either the next n terms or the next p terms, then prove that (m+n)(1/m-1/p)=(m+p)(1/m-1/n)dot

If the sum of m terms of an A.P. is equal to the sum of either the next n terms or the next p terms, then prove that (m+n)(1/m-1/p)=(m+p)(1/m-1/n)dot

If the sum of m terms of an A.P. is equal to the sum of either the next n terms or the next p terms, then prove that (m+n)(1/m-1/p)=(m+p)(1/m-1/n)dot

If the sum of m terms of an A.P. is equal to the sum of either the next n terms or the next p terms, then prove that (m+n)(1/m-1/p)=(m+p)(1/m-1/n)dot