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(frac(-1)(5))^(3) div (frac(-1)(5))^(8)=...

`(frac(-1)(5))^(3) div (frac(-1)(5))^(8)=` ?

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(frac(-2)(5))^(7) div (frac(-2)(5))^(5)= ?

(frac(-2)(3))^(10) div (frac(-2)(3))^(8)= ?

{(frac(1)(3))^(-3)-(frac(1)(2))^(-3)} div (frac(1)(4))^(-3)= ?

(frac(-5)(3))^(-1)= ?

Express each of the following as a rational number: ( i ) 5^(-3) ( ii ) (-2)^(-5) ( iii ) (frac(1)(4))^(-4) ( iv ) (frac(-3)(4))^(-3) ( v ) (-3)^(-1) xx (frac(1)(3))^(-1) ( vi ) (frac(5)(7))^(-1) xx (frac(7)(4))^(-1) ( vii ) (5^(-1)-7^(-1))^(-1) ( viii ) {(frac(4)(3))^(-1)-(frac(1)(4))^(-1)}^(-1) ( ix ) {(frac(3)(2))^(-1) div (frac(-2)(5))^(-1)} ( x ) (frac(23)(25))^(@)

Simplify: ( i ) [{(frac(-1)(4))^(2)}^(-2)]^(-1) ( ii ) {(frac(-2)(3))^(2)}^(3) ( iii ) (frac(-3)(2))^(2) div (frac(-3)(2))^(6) ( iv ) (frac(-2)(3))^(7) div (frac(-2)(3))^(4)

Find x such that (frac(3)(5))^(3) xx (frac(3)(5))^(-6)=(frac(3)(5))^(2x-1).

If (frac(5)(3))^(-5) xx (frac(5)(3))^(11)=(frac(5)(3))^(8x), then x = ?

(frac(1) (216))^(frac(2)(3)) div (frac(1)(27))^(frac(4)(3)) is equal to (A) frac(3)(4) (B) frac(2)(3) (C ) frac(4)(9) (D) frac(1)(8)

Write each of the following in power notation: ( i ) frac(5)(7)xxfrac(5)(7)xxfrac(5)(7)xxfrac(5)(7) ( ii ) (frac(-4)(3)) xx (frac(-4)(3)) xx (frac(-4)(3)) xx (frac(-4)(3)) xx (frac(-4)(3)) ( iii ) (frac(-1)(6)) xx (frac(-1)(6)) xx (frac(-1)(6)) ( iv ) (-8) xx (-8) xx (-8) xx (-8) xx (-8)