The relation between the`"energy" E `and the freqency ` v `of a photon is repressed by the equation` E = hv `, where h is plank's Writen down ` s_(t) = u + (a)/(2) (2t-1)` , where u is initial of h and its dimensions.

The relation between the "energy" E and the frequency v of a photon is repressed by the equation E = hv , where h is plank's constant Write down its dimensions.

As per quantum theory the energy E of a photon is related to its frequency nu as E = h nu , where h nu = Planck's constant. Then the dimension of h would be

What is the relation between H_1,H_2 , u and v.

Find the dimensions of Planck's constant h from the equatioin E=hv where E is the energy and v is the frequency.

Find the dimensions of Planck's constant h from the equatioin E=hv where E is the energy and v is the frequency.

What is the relation between h_(1),h_(2) , u and v.

If the enrgy of a frequency v is gives by E = hv where h is plank's constant and the momentum of photon is p = h//lambda where lambda is the wavelength of photon , then the velocity of light is equal to

If the enrgy of a frequency v is gives by E = hv where h is plank's constant and the momentum of photon is p = h//lambda where lambda is the wavelength of photon , then the velocity of light is equal to

We may state that the energy E of a photon of frequency v is E =hv, where h is a plank's constant. The momentum p of a photon is p=h//lambda where lambda is the wavelength of the photon. From the above statement one may conclude that the wave velocity of light is equal to

Check the correctness of the relation s_(t) = u+ (a)/(2) (2t-1) where u is initial velocity a is acceleration and s_(t) is the diplacement of the body in t^(th) second .