उस वृत्त का समीकरण ज्ञात कीजिए जो वृत्त `x^(2)+y^(2)+8x+10y-7=0` के केन्द्र से होकर जाता है तथा वृत्त `2x^(2)+2y^(2)-8x-12y-9=0` के संकेन्द्रीय है।

Two circles x^(2) + y^(2) - 4x + 10y + 20 = 0 and x^(2) + y^(2) + 8x - 6y - 24= 0

For the parabola y^(2)+8x-12y+20=0

(i) Centre of the circle x^(2) + y^(2) - 8x + 10 y + 12 = 0 is Centre of the circle 2x^(2) + 2y^(2) -x = 0 is :

Find the equation of the circle which passes through the centre of the circle x^(2)+y^(2)+8x+10y-7=0 and is concentric with the circle 2x^(2)+2y^(2)-8x-12y-9=0

(i) Find the equation of a circle , which is concentric with the circle x^(2) + y^(2) - 6x + 12y + 15 = 0 and of double its radius. (ii) Find the equation of a circle , which is concentric with the circle x^(2) + y^(2) - 2x - 4y + 1 = 0 and whose radius is 5. (iii) Find the equation of the cricle concentric with x^(2) + y^(2) - 4x - 6y - 3 = 0 and which touches the y-axis. (iv) find the equation of a circle passing through the centre of the circle x^(2) + y^(2) + 8x + 10y - 7 = 0 and concentric with the circle 2x^(2) + 2y^(2) - 8x - 12y - 9 = 0 . (v) Find the equation of the circle concentric with the circle x^(2) + y^(2) + 4x - 8y - 6 = 0 and having radius double of its radius.

The angle at which the circles x^(2) + y^(2) + 8x - 2y - 9 = 0 , x^(2) + y^(2) - 2x + 8y - 7 = 0 in tersect is

Show that the circles x^(2) + y^(2) + 2 x -6 y + 9 = 0 and x^(2) +y^(2) + 8x - 6y + 9 = 0 touch internally.

Find the centre and radius of circles. x^(2)+y^(2)-8x+10y-12=0 .

The radius of the circle : x^2 + y^2-8x + 10y- 12 =0 is: