`"I f"tantheta=a/b ,"t h e n"(sintheta)/(cos^8theta)+(costheta)/(sin^8theta)=`

(sintheta+sin 2theta)/(1+costheta+cos2theta)=

(sintheta+sin2theta)/(1+costheta+cos2theta) =

If A= tan27theta - tantheta and B= (sintheta)/(cos 3theta) +(sin 3theta)/(cos 9theta) + (sin 9theta)/(cos 27theta) , then the value of (A+B)/(A-B) +(A-B)/(A+B) -10/3 is

If A= tan27theta - tantheta and B= (sintheta)/(cos 3theta) +(sin 3theta)/(cos 9theta) + (sin 9theta)/(cos 27theta) , then the value of (A+B)/(A-B) +(A-B)/(A+B) -10/3 is

Simplify: (sin(90-theta)costheta)/(cos(90-theta)sintheta)+1=

Prove that (sintheta +sin2theta)/(1+costheta +cos2theta)=tantheta

Prove that tantheta=(sintheta-2sin^3theta)/(2cos^3theta-costheta)

Prove that : (sintheta +sin2theta)/(1+costheta+cos2theta)=tantheta

If tantheta=1 , then the value of (8sintheta+5cos theta)/(sin^(3)theta-2cos^(3)theta+7costheta) is

Prove that (sintheta-2sin^3theta)/(2cos^3theta-costheta)=tantheta .