" If "x" is very large as compare to "y," then the value of "k" in "sqrt((x)/(x+y))sqrt((x)/(x-y))=1+(y^(2))/(kx^(2))

If x is very large as compare to y,then the value of kin sqrt((x)/(x+y))sqrt((x)/(x-y))=1+(y^(2))/(kx^(2))

If x is very large as compare to y, then prove that sqrt((x)/(x+y))*sqrt((x)/(x-y))=1+(y^(2))/(2x^(2))

If x is very large as compare to y , then prove that sqrt(x/(x+y))dotsqrt(x/(x-y))=1+(y^2)/(2x^2) .

If x is very large as compare to y , then prove that sqrt(x/(x+y))dotsqrt(x/(x-y))=1+(y^2)/(2x^2) .

If x is very large as compare to y , then prove that sqrt(x/(x+y))dotsqrt(x/(x-y))=1+(y^2)/(2x^2) .

If 2^(x + y ) = 2^(x - y ) = sqrt8 then the value of y is

If x,y in R satisfy the equation x^(2)+y^(2)-4x-2y+5=0, then the value of the expression ((sqrt(x)-sqrt(y))^(2)+4sqrt(xy))/((x+sqrt(xy))) is

find x and y 3/sqrt(x)+1/sqrt(x)=sqrt(x) y^2-(7)^(5/2)/sqrt(y)=0