The temperature of the source and the sink of a heat engine are `127^(@)C and 27^(@)C` respectively, An inventor claims its efficiency to be 30%, then

The efficiency of a heat engine working between 27^(@)C and 127^(@)C is:

A Carnot engine working in a cycle absorbs 10^4 calories. If the temperature of the source and the sink are 327^@C and 27^@C respectively, calculate the heat rejected to the sink.

If the temperature of the sink of a Carnot engine having an efficiency (1)/( 6) is reduced by 62^(@)C , then its efficiency is doubled. Find the temperature of the sink and source respectively.

If the temperature of the sink of a Carnot engine having an efficiency (1)/( 6) is reduced by 62^(@)C , then its efficiency is doubled. Find the temperature of the sink and source respectively.

A heat engine works between source and sink temperatures 150°C and 30°C respectively.The efficiency of heat engine may be

A heat engine works between source and sink temperatures 150°C and 30°C respectively.The efficiency of heat engine may be

The temperature of sink of Carnot engine is 27^(@) C. Efficiency of engine is 25%. Then temperature of source is