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The line passing through (-1, pi/2) and ...

The line passing through `(-1, pi/2)` and perpendicular to `sqrt(3)sintheta+2costheta=4/r`is

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The line passing through (-1,(pi)/(2)) and perpendicular to sqrt(3)sin theta+2cos theta=(4)/(r) is

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The line passing through (-1,pi/2) and perpendicular to sqrt3 sin(theta) + 2 cos (theta) = 4/r is

The line passing through (-1,pi/2) and perpendicular to sqrt3 sin(theta) + 2 cos (theta) = 4/r is

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sqrt(3)sintheta-costheta=sqrt(2)

sqrt(3)costheta+sintheta=2

Solve sqrt3sintheta-costheta=sqrt2

sintheta+costheta=sqrt(2)