If sets A and B defines as `A={(x,y),y=(1)/(x),0 ne x in R}` and B={(x,y)}:y=-x, `x in R` then

IF sets A and B are defined as A={(x,y):y-(1)/(x),0ne x in R} B= {(x,y):y=-x,x in R}, then

If the sets A and B are defined as : A={(x,y):y =1/x ,0 ne x in R} , B={(x,y) : y=-x , x in R}, then :

If sets A and B are defined as A= {(x, y)|y = (1)/(x), x ne 0 in R}, B= {(x, y)| y= -x, x in R} . Then,

A={(x,y):y=(1)/(x),0!=x in R} and B={(x,y):y=-x,x in R} ,then write A nn B.

If set A and B are defined as A = {(x,y)|y = 1/x, 0 ne x in R}, B = {(x,y)|y = -x , x in R,} . Then

If set A and B are defined as A = {(x,y)|y = 1/x, 0 ne x in R}, B = {(x,y)|y = -x , x in R,} . Then

If set A and B are defined as A = {(x,y)|y = 1/x, 0 ne x in R}, B = {(x,y)|y = -x , x in R,} . Then

If set A and B are defined as A = {(x,y)|y = 1/x, 0 ne x in R}, B = {(x,y)|y = -x , x in R,} . Then

If set A and B are defined as A = {(x,y)|y = 1/x, 0 ne x in R}, B = {(x,y)|y = -x , x in R,} . Then (a) A ∩ B = A (b)A ∩ B = B (c)A ∩ B = ϕ (d)A ∪ B = A

A = {(x,y) : y = 1//x,0 ne x in R} , B = {(x, y) : y = - x, x in R} then