In a tringle ABC, AB = AC and bisector of angle A meets BC at D. Prove that :
(i) `DeltaABD cong DeltaACD` (ii) `AD` is perpendicular to BC.

ABC is a right angled with AB=AC. Bisector of angleA meets BC at D. prove that BC=2AD

In DeltaABC , AC > AB and bisector of angleA meets BC and D then angleADB is :

ABC is a right triangle with AB = AC .If bisector of angle A meet BC at D then prove that BC = 2 AD .

ABC is a right triangle with AB = AC.If bisector of angle A meet BC at D then prove that BC =2 AD .

In DeltaABC , AC > AB . The bisector of angleA meets BC at D. Prove that angleADB is an acute angle.

In a triangle ABC , AB = AC and angle A = 36^(@) If the internal bisector of angle C meets AB at D . Prove that AD = BC.

In given figure AB = AC and BD = DC. Prove that DeltaABD~=DeltaACD

In a DeltaABC , BC = 9 cm, AC = 40 cm and AB = 41 cm. If bisector of angle A meets side BC at D then ratio of area of DeltaABD and DeltaABC is

ABC is a right triangle such that AB=AC and bisector of angle C intersects the side AB at D. prove that AC+AD=BC.