`CaCO_(3)(s) hArr CaO(s)+CO_(2)(g)` in closed container at equilibrium. What would be the effect of addition of `CaCO_(3)` on the equilibrium concentration of `CO_(2)`.

The reaction CaCO_(3)(s) hArr CaO(s)+CO_(2)(g) reaches the state of equilibrium when

The reaction CaCO_(3)(s) hArr CaO(s)+CO_(2)(g) reaches the state of equilibrium when

For CaCO_(3)(s) hArr CaO(s)+CO_(2)(g), K_(c) is equal to …………..

For CaCO_(3)(s) hArr CaO(s)+CO_(2)(g), K_(c) is equal to …………..

The given reaction is carried out in a closed vessel: CaCO_(3)(s)hArr CaO(s)+CO_(2)(g), DeltaH^(0) gt0 . What would be the effect of the following changes on the equilibrium of the reaction if (1) solid CaCO_(3) is added to the reaction system, (2) some amount of CaO is removed from the reaction system, (3) CO_(2)(g) is introduced into the reaction system at constant volume and temperature., (4) temperature is increased, and (5) volume of the reaction vessel is reduced at constant temperature.

For CaCO_(3)(S) hArr CaO(s) + CO_(2) (g), Delta H = + Q at equilibrium. to shift equilibrium towards right,

For CaCO_(3)(S) hArr CaO(s) + CO_(2) (g), Delta H = + Q at equilibrium. The addition of more CaCO3(s) causes?

For the reaction CaCO_(3)(s) hArr CaO(s) + CO_(2)(g) was put in to 10 L container and heated to 800^(@)C , what percentage of the CaCO_(3) would remain unreacted at equilibrium. if 'k_(p)' is 1.16 atm and 'CaCO_(3)(s)' initially is 20g

CaCO_(3)(s) hArr CaO(s)+CO_(2)(g) For the equilibrium , it is found that log K_(p)=8-(6400(K))/(T) T=527^(@)C if :