If .^(20)C(r)=.^(20)C(r-10) then find th...

If `.^(20)C_(r)=.^(20)C_(r-10)` then find the value of `.^(17)C_(r)`.

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The correct Answer is:

136

`r+r-10=20rArr r=15`. So, `.^(17)C_(r)=.^(17)C_(15)=.^(17)C_(2)=(17xx16)/(2xx1)=136`.

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