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The radius of the wheel of a vehicle is 42 cm. How many revolutioins will it complete in a 19.8-km-long journey?

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To solve the problem of how many revolutions a wheel with a radius of 42 cm will complete in a 19.8 km journey, we can follow these steps: ### Step-by-Step Solution: 1. **Convert the distance from kilometers to centimeters:** \[ \text{Distance} = 19.8 \text{ km} = 19.8 \times 1000 \text{ m} = 19800 \text{ m} = 19800 \times 100 \text{ cm} = 1980000 \text{ cm} \] **Hint:** Remember that 1 km = 1000 m and 1 m = 100 cm. 2. **Calculate the circumference of the wheel:** The circumference \( C \) of a circle (which represents the distance covered in one complete revolution of the wheel) is given by the formula: \[ C = 2 \pi R \] where \( R \) is the radius of the wheel. Substituting \( R = 42 \) cm: \[ C = 2 \times \frac{22}{7} \times 42 \] **Hint:** Use \( \pi \approx \frac{22}{7} \) for calculations. 3. **Calculate the circumference:** \[ C = 2 \times \frac{22}{7} \times 42 = \frac{1848}{7} \text{ cm} \] \[ C \approx 264 \text{ cm} \] **Hint:** Perform the multiplication and division carefully to find the circumference. 4. **Determine the number of revolutions:** The number of revolutions \( N \) can be calculated by dividing the total distance traveled by the circumference of the wheel: \[ N = \frac{\text{Total Distance}}{\text{Circumference}} = \frac{1980000 \text{ cm}}{264 \text{ cm}} \] **Hint:** Ensure that both the total distance and circumference are in the same units (cm). 5. **Calculate the number of revolutions:** \[ N = \frac{1980000}{264} \approx 7500 \] **Hint:** Perform the division to find the total number of revolutions. ### Final Answer: The wheel will complete approximately **7500 revolutions** during the 19.8 km journey.

To solve the problem of how many revolutions a wheel with a radius of 42 cm will complete in a 19.8 km journey, we can follow these steps: ### Step-by-Step Solution: 1. **Convert the distance from kilometers to centimeters:** \[ \text{Distance} = 19.8 \text{ km} = 19.8 \times 1000 \text{ m} = 19800 \text{ m} = 19800 \times 100 \text{ cm} = 1980000 \text{ cm} \] ...
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RS AGGARWAL-AREA OF CIRCLE, SECTOR AND SEGMENT -Exercise 16A
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  2. The area of a circle inscribed in an equilateral triangle is 154\ c...

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  3. The radius of the wheel of a vehicle is 42 cm. How many revolutioins w...

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  4. The wheels of the locomotive of a train are 2.1 m in radius. They make...

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  5. The wheels of a car make 2500 revolutions in covering a distance of 4....

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  6. A boy is cycling such that the wheels of the cycle are making 140 r...

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  7. The wheel of a motor cycle is of radius 35 cm. How many revolutions pe...

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  8. The diameters of the fron and rear wheels of a tractor are 80 cm and 2...

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  9. Four equal circles are described about the four corners of square so ...

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  10. Four equal circles each of radius 5 cm, touch each other, as shown in ...

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  11. Four circles each of radius ' a ' units touch one another. The a...

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  12. Three equal circles, each of radius 6 cm, touch one another as shown i...

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  13. If three circles of radius a each are drawn such that each touches the...

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  14. In the given figure ABCD s a trapezium of area 24.5cm^(2). If AD||BC, ...

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  15. ABCD is a field in the shape of a trapezium, AD||BC,/ABC=90^(@) and /A...

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  16. Find the area of the shaded region in the given figure, where a circul...

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  17. In the given figure, ABCD is a rectangle with AB=80cm and BC=70cm, /AE...

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  18. In the given figure, from a rectangular region ABCD with AB=20cm a rig...

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  19. In the given figure O is the centre of the circle with AC=24cm, AB=7cm...

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  20. In the given figure, a circle is inscribed in an equilateral triangle ...

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