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The wheels of the locomotive of a train ...

The wheels of the locomotive of a train are 2.1 m in radius. They make 75 revolutions in one minute. Find the speed of the train in km per hour.

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To find the speed of the train in kilometers per hour, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the radius of the wheel**: The radius \( r \) of the wheel is given as 2.1 meters. 2. **Calculate the circumference of the wheel**: The distance covered in one revolution of the wheel is the circumference, which is calculated using the formula: \[ \text{Circumference} = 2 \pi r \] Substituting the value of \( r \): \[ \text{Circumference} = 2 \times \pi \times 2.1 \] Approximating \( \pi \) as \( \frac{22}{7} \): \[ \text{Circumference} = 2 \times \frac{22}{7} \times 2.1 \] 3. **Calculate the total distance covered in 75 revolutions**: The total distance \( D \) covered in 75 revolutions is: \[ D = \text{Circumference} \times \text{Number of Revolutions} \] Thus: \[ D = 2 \times \frac{22}{7} \times 2.1 \times 75 \] 4. **Convert the distance from meters to kilometers**: Since 1 kilometer = 1000 meters, we convert the distance to kilometers: \[ D_{km} = \frac{D}{1000} \] 5. **Calculate the time taken in hours**: The time taken for 75 revolutions is given as 1 minute. To convert this to hours: \[ \text{Time} = \frac{1}{60} \text{ hours} \] 6. **Calculate the speed of the train**: Speed is calculated using the formula: \[ \text{Speed} = \frac{\text{Distance}}{\text{Time}} \] Substituting the values we have: \[ \text{Speed} = \frac{D_{km}}{\frac{1}{60}} = D_{km} \times 60 \] 7. **Final Calculation**: Now we substitute the values and calculate: \[ D = 2 \times \frac{22}{7} \times 2.1 \times 75 \] \[ D = 2 \times \frac{22}{7} \times 2.1 \times 75 = \frac{2 \times 22 \times 2.1 \times 75}{7} \] \[ D = \frac{2 \times 22 \times 2.1 \times 75}{7} \approx 594 \text{ meters} \] Converting to kilometers: \[ D_{km} = \frac{594}{1000} = 0.594 \text{ km} \] Now calculating speed: \[ \text{Speed} = 0.594 \times 60 \approx 35.64 \text{ km/h} \] ### Final Answer: The speed of the train is approximately **35.64 km/h**.

To find the speed of the train in kilometers per hour, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the radius of the wheel**: The radius \( r \) of the wheel is given as 2.1 meters. 2. **Calculate the circumference of the wheel**: ...
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RS AGGARWAL-AREA OF CIRCLE, SECTOR AND SEGMENT -Exercise 16A
  1. The area of a circle inscribed in an equilateral triangle is 154\ c...

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  2. The radius of the wheel of a vehicle is 42 cm. How many revolutioins w...

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  3. The wheels of the locomotive of a train are 2.1 m in radius. They make...

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  4. The wheels of a car make 2500 revolutions in covering a distance of 4....

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  5. A boy is cycling such that the wheels of the cycle are making 140 r...

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  6. The wheel of a motor cycle is of radius 35 cm. How many revolutions pe...

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  7. The diameters of the fron and rear wheels of a tractor are 80 cm and 2...

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  8. Four equal circles are described about the four corners of square so ...

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  9. Four equal circles each of radius 5 cm, touch each other, as shown in ...

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  10. Four circles each of radius ' a ' units touch one another. The a...

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  11. Three equal circles, each of radius 6 cm, touch one another as shown i...

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  12. If three circles of radius a each are drawn such that each touches the...

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  13. In the given figure ABCD s a trapezium of area 24.5cm^(2). If AD||BC, ...

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  14. ABCD is a field in the shape of a trapezium, AD||BC,/ABC=90^(@) and /A...

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  15. Find the area of the shaded region in the given figure, where a circul...

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  16. In the given figure, ABCD is a rectangle with AB=80cm and BC=70cm, /AE...

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  17. In the given figure, from a rectangular region ABCD with AB=20cm a rig...

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  18. In the given figure O is the centre of the circle with AC=24cm, AB=7cm...

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  19. In the given figure, a circle is inscribed in an equilateral triangle ...

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  20. The perimeter of the quadrant of a circle is 25 cm. Find the area.

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