A sector of 56^(@), cut out from a circl...

A sector of `56^(@)`, cut out from a circle, contains `17.6cm^(2)`. Find the radius of the circle.

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The correct Answer is:

`6cm`

`(pir^(2)theta)/360=17.6implies22/7xxr^(2)xx56/360=17.6impliesr^(2)=36impliesr=6cm`

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