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In the given figure, Oa = OB and OC = OD...

In the given figure, Oa = OB and OC = OD. Which is the criteria to prove
`DeltaAOC ~=DeltaBOD`.

A

`SAS`

B

`ASA`

C

`SSS`

D

NONE OF THESE

Text Solution

Verified by Experts

The correct Answer is:
A
(i) In `DeltaOAC and DeltaOBD,` we have
Oa = OB (given),
OC = OD (given)
and `angleAOC=angleBOD" "("vertically opposite "angles).`
`therefore" "DeltaOAC~=DeltaOBD" (by SAS-criteria)."`
(ii) `"We have, "DeltaOAC~=DeltaOBD" (proved above)"`
`therefore" "angleOAC=angleOBD" (c.p.c.t)."`
But, there are alternate angles.
`therefore" "AC"||"BD.`
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