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Prove that each angle of an equilater...

Prove that each angle of an equilateral triangle is `60^0`

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Let `DeltaABC` be an equilateral triangle.
Then, BC = CA = AB
`rArr" "BC=CA and CA=AB`
`rArr" "angleA=angleB and angleB=angleC`
`" "[because" angles opposite to equal sides are equal"]`
`rArr" "angleA=angleB=angleC=x^(@)" (say)"`.
But, we know that the sum of all angles of a triangle is `180^(@)`.
`therefore" "angleA+angleB+angleC=180^(@)`
`rArr" "x^(@)+x^(@)+x^(@)=180^(@)`
`rArr" "3x^(@)=180^(@)rArr x=60.`
`therefore" "angleA=angleB=angleC=60^(@)`
Hence, each angle of an equilateral triangle is `60^(@)`.
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