In DeltaABC,D is the midpoint of BC. If ...

In `DeltaABC,D` is the midpoint of BC. If `DL_|_AB` and `DM_|_AC` such that DL = DM, prove that AB = AC.

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`DeltaBDL~=DeltaCDM` as `BD=CD, DL=DM, angleBLD=angleCMD=90^(@)`.
`therefore" "angleB=angleC and " hence "AB=AC.`

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