Two teams are pulling a rope with equal and opposite forces each of 5 kN in a tug of war so that a condition of equilibrium exists. What will be the tensile force in the rope?

Options

A. Zero
B. 2.5 kN
C. 5 kN
D. 10 kN

Explanation

To solve the problem, we need to analyze the situation of the tug of war between the two teams pulling on the rope.

### Step 1: Understand the Forces Acting on the Rope
In a tug of war, two teams are pulling on a rope with equal and opposite forces. In this case, each team is pulling with a force of 5 kN.

### Step 2: Apply the Condition of Equilibrium
For the rope to be in a state of equilibrium, the net force acting on the rope must be zero. This means that the forces exerted by both teams must balance each other out.

### Step 3: Calculate the Tensile Force in the Rope
Since both teams are pulling with equal forces of 5 kN in opposite directions, the tensile force in the rope is equal to the force exerted by one team. Therefore, the tensile force in the rope is:

\[ \text{Tensile Force} = 5 \, \text{kN} \]

### Conclusion
The tensile force in the rope is 5 kN.

---