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In the relation alpha+beta t + lamda, al...

In the relation `alpha+beta t + lamda, alpha and lamda` are measured in meter (m) and tis measured in second (s). The SI unit of `beta` must be

A

m

B

ms

C

s

D

`ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
`alpha=beta t + lamda" "[alpha-"meter, t-second"]`
`beta=(m)/(s)=ms^(-1)`
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