A person stands on his two feet over a surface and experiences a pressure P. Now the person stands on only one foot. He would experience a pressure of magnitude

Options

A. `4 P`
B. P
C. `(1)/(2)P`
D. `2 P`

Explanation

To solve the problem, we need to understand the relationship between force, area, and pressure. The pressure experienced by a person standing on a surface is given by the formula:

\[ P = \frac{F}{A} \]

where:
- \( P \) is the pressure,
- \( F \) is the force (weight of the person), and
- \( A \) is the area of contact with the surface.

### Step-by-Step Solution:

1. **Identify the Initial Condition**:
When the person stands on both feet, he experiences a pressure \( P \). Let’s denote the force (weight of the person) as \( F \) and the area of contact when standing on both feet as \( A \).

\[ P = \frac{F}{A} \]

2. **Determine the Area of Contact**:
When the person is standing on both feet, let’s assume the area of contact is \( A \).

3. **Change the Condition**:
Now, when the person stands on only one foot, the area of contact with the surface is reduced. If we assume that the area of contact when standing on one foot is \( \frac{A}{2} \) (since he is now using only one foot), we need to find the new pressure \( P' \).

4. **Calculate the New Pressure**:
The new pressure \( P' \) when standing on one foot can be calculated using the same formula for pressure:

\[ P' = \frac{F}{\frac{A}{2}} = \frac{F \cdot 2}{A} = 2 \cdot \frac{F}{A} \]

5. **Relate New Pressure to Initial Pressure**:
Since \( P = \frac{F}{A} \), we can substitute this into our equation for \( P' \):

\[ P' = 2P \]

### Conclusion:
When the person stands on one foot, he experiences a pressure of magnitude \( 2P \).