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The force acting on a particle of mass m...

The force acting on a particle of mass m moving along the x-axis is given by `F (x) = Ax^(2) - Bx.`
Which one of the following is the potential energy of the particle?

A

2 Ax-B

B

`-(x^(2))/(6)(2Ax-B)`

C

`Ax^(3)-Bx^(2)`

D

Zero

Text Solution

Verified by Experts

The correct Answer is:
B

Potential energy `=-int F(x) dx`
`U(x)=-int (Ax^(2)-BX)dx`
`U(x)=-A(x^(3))/(3)+B(x^(2))/(2)`
`U(x)=-x^(2)//6(2Ax-3B)`
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