A one-rupee coin is placed at the bottom of a vessel. Water
is then poured into the vessel such that the depth of water
becomes 20 cm. If water has refractive index 4/3, the coin
would be seen at a depth of

Options

A. a 20 cm
B. b about 26 cm
C. c 15 cm
D. d 25 cm

Answer

C

Explanation

Here, `mu=4/3`
real depth = 20 cm
apparent depth = ?
We have, `mu= ("real depth")/("apparent depth")`
`rArr "apparent depth"=("real depth")/mu=(20xx3)/4=15 cm.`