If the reaction of 1.0 mol `NH_(3)(g)` and 1.0 mol `O_(2)(g)4NH_(3)(g)+5O_(2)(g)to4NO(g)+6H_(2)O(l)` is carried to completion, then

Options

A. all the `O_(2)(g)` is produced
B. 4.0 mol NO (g) is produced
C. 1.5 mol `H_(2)O`(l) is produced
D. all the `NH_(3)(g)` is consumed

Answer

A

Explanation

`4NH_(3) +5O_(2) to 4NO +6H_(2)O`
4 mol 5 mol
1 mol `(5)/(4) =1.25` mol
Since for 1 mol of `NH_(3) , 1.25 ` mol of `O_(2)` required therefore `O_(2)` is the limiting factor (here `O_(2)` is only 1 mol) Hence all `O_(2)` will be consumed in reaching wiht 1 mol fo `NH_(3)`