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[" 40."sin^(2)24^(0)-sin^(2)6^(0)=],[[" ...

[" 40."sin^(2)24^(0)-sin^(2)6^(0)=],[[" 1."(sqrt(5)+1)/(8)," 2."(sqrt(5)-1)/(8)," 3."(sqrt(5)+2)/(8)," 4."(sqrt(5)-2)/(8)]]

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sin ^(2) 24 ^(@) - sin ^(2) 6^(@) = (sqrt5 -1)/(8).

Prove that: sin^(2)24^(0)-sin^(2)6^(0)=(sqrt(5)-1)/(8)

Prove that: sin^(2)24^(0)-sin^(2)6^(0)=(sqrt(5)-1)/(8)

sin^(2)24^(@)-sin^(2)6^(@) is equal to

Prove that sin^(2)24^(@)-sin^(2)6^(@)

4(sin24^(0)+cos6^(@))=sqrt(3)+sqrt(15)

2 sin 40^(@) sin 10^(@)=

sin20^(0)sin40^(0)sin60^(0)sin80^(@)=(3)/(16)

Prove that: sin^2 24^0-sin^2 6^0=(sqrt(5)-1)/8