[" (2) "(x+y+1)(dy)/(dx)=1],[" Q "(tan^(-1)y-x)dy=(1+y^(2))]

(1+x^(2))(dy)/(dx)+y=e^(tan^(-1)x)

(1+x^(2))(dy)/(dx)+y=e^(tan^(-1)x)

(1+x^(2))(dy)/(dx)+y=e^(tan^(-1)x)

(1+x^(2))(dy)/(dx)+y=e^(tan^(-1)x)

(dy)/(dx)=1+x tan(y-x)

Solve :(1+y^(2))dx=(tan^(-1)y-x)dy

Solve: (1+x^2)(dy)/(dx) = y+tan^(-1)x

Solve the following differential equations (i) (1+x^(2)) (dy)/(dx) + y = e^(tan^(-1))x (ii) (1+x^(2))(dy)/(dx) + y = tan^(-1)x

(x (dy) / (dx) -y) tan ^ (- 1) ((y) / (x)) = x