5x + 10 y - 15 z = 5 (x + 2y - 3z)

The system of equation 2x + y - 3z = 5 3x - 2y + 2z = 5 5x - 3y - z = 16

The plane 2x - y + 4z = 5 , 5x - 2.5y + 10z = 6 are :

The planes 2x - y + 4z = 5 and 5x - 2.5y + 10z = 6 are :

The planes : 2x - y + 4z = 5 and 5x - 2.5y + 10z = 6 are

Prove that the lines 3x + 2y + z – 5 = 0 = x + y – 2z – 3 and 2x – y – z = 0 = 7x + 10y – 8z – 15 are perpendicular

The planes 2x - y + 4z = 3 and 5x - 2.5y + 10z = 6 are :

If (x,y,z) is the solution of the equations 4x + y = 7 3y + 4z = 5 5x + 3z = 2 Then the value of x + y + z equals

Add: 5x - 8y + 2z, 3z - 4y - 2x, 6y - z - x and 3x - 2z - 3y

Add the following: (i) x – 3y – 2z , 5x + 7y – 8z , 3x – 2y + 5z