In `DeltaABC` if `AD` is the altitude and `O` is the orthocentre of `DeltaABC` then `AO : OD=`

In Delta ABC if AD is the altitude and O is the orthocentre of Delta ABC then AO:OD=

If H is the orthocentre of DeltaABC , then AH is

If S is the circumcentre, O is the orthocentre of DeltaABC, then bar(SA) + bar(SB)+bar(SC) equals

If (3, -2) is the orthocentre and (-1, 4) is the circumcentre of DeltaABC then centroid of DeltaABC is

If S is circumcentre, O is orthocentre of DeltaABC , then vec(SA)+vec(SB)+vec(SC) =

O is orthocentre of DeltaABC if angleBOC=120^(@) find angleBAC

If in a DeltaABC, AD, BE and CF are the altitudes and R is the circumradius, then the radius of the circumcircle of DeltaDEF is

(xi) O is the orthocentre of the DeltaABC If angle BAC=55^@ , then angle BOC=

In the given figure, AD is altitude and AE is bisector of angle BAC of DeltaABC . Show that DeltaDAE=(1)/(2)(angleB-angleC)