A `120 V, 60 Hz` a.c. power is connected `800 Omega` non-inductive resistance and unknown capacitance in series. The voltage drop across the resistance is found to be `102 V`, then voltage drop across capacitor is

A 120 V, 60 Hz power source is connected across an 800 Omega non inductive resistance and an unkown capacitance in series. The voltage drop across the resistor is 102 V. (a) What is the voltahe drop acorss the capacitor ? (b) What is the reactance of the capacitor ?

In the above circuit, the voltage drop across the resistance (R) is

In series LCR circuit voltage drop across resistance is 8V, across inductor is 6V and across capacitor is 12V. Then

In series LCR circuit voltage drop across resistance is 8V, across inductor is 6V and across capacitor is 12V. Then

In series L-C-R circuit, voltge drop across resistance is 8V , across inductor is 6V and across capacitor is 12V . Then,

In series L-C-R circuit, voltge drop across resistance is 8V , across inductor is 6V and across capacitor is 12V . Then,

For the circuit shown in Fig. find the voltage drop across series resistance,

An alternating voltage is connected in series with a resistance R and inductance L if the potential drop across the resistance is 200V and across the inductance is 150V , then the applied voltage is

An alternating voltage is connected in series with a resistance R and inductance L if the potential drop across the resistance is 200V and across the inductance is 150V , then the applied voltage is