`ydx + xdy = xy(dy -dx)`

The solution of x dx + y dy = 2 (xdy-ydx) is

The solution of ydx - xdy = xydx is

Solve: xdx + y dy + xdy - ydx = 0

Solve (i) xdx +ydy + (xdy - ydx)/(x^(2) + y^(2)) = 0 (ii) y(1+xy) dx - xdy = 0

Solve x^2dy+y^2dx=xy(xdy-ydx)

The solution of cos((x)/(y))(ydx-xdy)=xy^(3)(xdy+ydx) is sin((x)/(y))=((xy)^(lambda))/(mu)+C then the value of (lambda+mu) is

Solve x dy + y dx = (ydx - xdy)/(x^2 + y^2)

Solve: ydx-xdy=xydy

Solve: ydx-xdy=xydy