A projectile is fired at speed v at an angle `theta` with horizontal. If radius of curvature at the tip equals half the maximum height, when `theta = tan^(-1) sqrtx`. What is x ?

A projectile is fired at an angle theta with the horizontal with velocity u. Deduce the expression for the maximum height reached by it.

A projectile is thrown with a speed v at an angle theta with the vertical. Its average velocity between the instants it crosses half the maximum height is

A projectile is thrown with a speed v at an angle theta with the vertical. Its average velocity between the instants it crosses half the maximum height is

A particle is projected with a speed u at an angle theta to the horizontal. Find the radius of curvature. At the point where the particle is at a highest half of the maximum height H attained by it.

A particle is projected with a speed u at an angle theta to the horizontal. Find the radius of curvature. At the point where the particle is at a highest half of the maximum height H attained by it.

A projectile is thrown with velocity v at an angle theta with the horizontal. When the projectile is at a height equal to half of the maximum height,. The velocity of the projectile when it is at a height equal to half of the maximum height is.

A projectile is thrown with velocity v at an angle theta with the horizontal. When the projectile is at a height equal to half of the maximum height,. The velocity of the projectile when it is at a height equal to half of the maximum height is.

A projectile is thrown with velocity v at an angle theta with the horizontal. When the projectile is at a height equal to half of the maximum height,. The vertical component of the velocity of projectile is.

A projectile is thrown with velocity v at an angle theta with the horizontal. When the projectile is at a height equal to half of the maximum height,. The vertical component of the velocity of projectile is.