Home
Class 11
CHEMISTRY
The enthalpy change for chemical reactio...

The enthalpy change for chemical reaction is denoted aas `DeltaH^(Theta)` and `DeltaH^(Theta) = H_(P)^(Theta) - H_(R)^(Theta)`. The relation between enthalpy and internal enegry is expressed by equation:
`DeltaH = DeltaU +DeltanRT`
where `DeltaU =` change in internal enegry `Deltan =` change in number of moles, `R =` gas constant.
`H_(2)(g) +((1)/(2))O_(2)(g) = H_(2)O(l), DeltaH_(298K) = - 68.00kcal`
Heat of voporisation of water at `1` atm and `25^(@)C` is `10.00 kcal`. The standard heat of formation (in kcal) of `1` amol vapour a `25^(@)C` is

Promotional Banner

Similar Questions

Explore conceptually related problems

The enthalpy change for chemical reaction is denoted aas DeltaH^(Theta) and DeltaH^(Theta) = H_(P)^(Theta) - H_(R)^(Theta) . The relation between enthalpy and internal enegry is expressed by equation: DeltaH = DeltaU +DeltanRT where DeltaU = change in internal enegry Deltan = change in number of moles, R = gas constant. Enthalpy of the system is given as

The enthalpy change for chemical reaction is denoted aas DeltaH^(Theta) and DeltaH^(Theta) = H_(P)^(Theta) - H_(R)^(Theta) . The relation between enthalpy and internal enegry is expressed by equation: DeltaH = DeltaU +DeltanRT where DeltaU = change in internal enegry Deltan = change in number of moles, R = gas constant. Enthalpy of the system is given as

The enthalpy change for chemical reaction is denoted as DeltaH^(Theta) and DeltaH^(Theta) = H_(P)^(Theta) - H_(R)^(Theta) . The relation between enthalpy and internal energy is expressed by equation: DeltaH = DeltaU +DeltanRT where DeltaU = change in internal energy Deltan = change in number of moles, R = gas constant. Enthalpy of the system is given as

The enthalpy change for chemical reaction is denoted aas DeltaH^(Theta) and DeltaH^(Theta) = H_(P)^(Theta) - H_(R)^(Theta) . The relation between enthalpy and internal enegry is expressed by equation: DeltaH = DeltaU +DeltanRT where DeltaU = change in internal enegry Deltan = change in number of moles, R = gas constant. For a reaction, 2X(s) +2Y(s) rarr 2C(l) +D(g), DeltaH at 27^(@)C is -28 kcal mol^(-1). DeltaU is ..... kcal mol^(-1)

The enthalpy change for chemical reaction is denoted aas DeltaH^(Theta) and DeltaH^(Theta) = H_(P)^(Theta) - H_(R)^(Theta) . The relation between enthalpy and internal enegry is expressed by equation: DeltaH = DeltaU +DeltanRT where DeltaU = change in internal enegry Deltan = change in number of moles, R = gas constant. For a reaction, 2X(s) +2Y(s) rarr 2C(l) +D(g), DeltaH at 27^(@)C is -28 kcal mol^(-1). DeltaU is ..... kcal mol^(-1)

The enthalpy change for chemical reaction is denoted aas DeltaH^(Theta) and DeltaH^(Theta) = H_(P)^(Theta) - H_(R)^(Theta) . The relation between enthalpy and internal enegry is expressed by equation: DeltaH = DeltaU +DeltanRT where DeltaU = change in internal enegry Deltan = change in number of moles, R = gas constant. Which of the following equations corresponds to the definition of enthalpy of formation at 298K ?

The enthalpy change for chemical reaction is denoted aas DeltaH^(Theta) and DeltaH^(Theta) = H_(P)^(Theta) - H_(R)^(Theta) . The relation between enthalpy and internal energy is expressed by equation: DeltaH = DeltaU +DeltanRT where DeltaU = change in internal energy Deltan = change in number of moles, R = gas constant. Which of the following equations corresponds to the definition of enthalpy of formation at 298K ?

The enthalpy change for chemical reaction is denoted as DeltaH^(Theta) and DeltaH^(Theta) = H_(P)^(Theta) - H_(R)^(Theta) . The relation between enthalpy and internal enegry is expressed by equation: DeltaH = DeltaU +DeltanRT where DeltaU = change in internal enegry Deltan = change in number of moles, R = gas constant. For the change, C_("diamond") rarr C_("graphite"), DeltaH =- 1.89 kJ , if 6g of diamond and 6g of graphite are seperately burnt to yield CO_(2) the heat liberated in first case is

The enthalpy change for chemical reaction is denoted as DeltaH^(Theta) and DeltaH^(Theta) = H_(P)^(Theta) - H_(R)^(Theta) . The relation between enthalpy and internal enegry is expressed by equation: DeltaH = DeltaU +DeltanRT where DeltaU = change in internal enegry Deltan = change in number of moles, R = gas constant. For the change, C_("diamond") rarr C_("graphite"), DeltaH =- 1.89 kJ , if 6g of diamond and 6g of graphite are seperately burnt to yield CO_(2) the heat liberated in first case is