`dy/dx=(x(2logx+1))/(siny+ycosy)`

Solve (dy)/(dx)=(x(2logx+1))/(siny+y cosy)

Solve the differential equation (dy)/(dx)=(2x(logx+1))/(siny+ycosy) , given that y=0,w h e nx=1.

Find the particular solution of the differential equation (dy)/(dx)=(x(2logx+1))/((siny+y cosy))," given that " y=(pi)/(2) " when " x =1.

Solution of (dy)/(dx)=(xlogx^(2)+x)/(siny+ycosy) is

x dy/dx+y=y^2 logx

x dy/dx+y=y^2 logx

x(dy)/(dx)=y(logy-logx+1)

x(dy)/(dx)=y(logy-logx-1)

x(dy)/(dx)=y(logy-logx+1)