The gap between the plates of a parallel plate capacitor is filled with glass of resistivity `rho`. The capacitance of the capacitor without glass equals C. The leakage current of the capacitor when a voltage V is applied to it is

The gap between the plates of a parallel-plate capacitor is filled with glass of resistivity rho = 100 G Omega m , The capacitance of the capacitors equals C = 4.0 nF . Find the leakeage current of the capacitor when a voltage V = 2.0 kV is applied to it.

The capacitance of a parallel plate capacitor increases with

The capacitance of a parallel plate capacitor depends on

In a parallel plate capacitor, the capacitance

The gap between the plates of a parallel plate capacitor is filled with glass of dielectric constant k=6 and of specific resistivity 100 G Omega m . The capacitance of the capacitor is 4.0mF . When a voltage of 2.0 kV is applied to the capacitor, the leakage current of the capacitor will be.

If the gap between the plates of a parallel plate capacitor is filled with medium of dielectric constant k=2 , then the field between them

A metal plate is introduced between the plates of a charged parallel plate capacitor. What is its effect on the capacitance of the capacitor?

What is a parallel plate capacitor? Derive an expression for the capacitance of a parallel plate capacitor?