If the time period of revolution of a planet is increased to `3sqrt(3)` times its present value, the percentage increase in its radius of the orbit of revolution is ______.

Show that the time period of revolution for any planet T^2propr^3 [r = radius of the circular path]

The period of revolution of a satellite in an orbit becomes 8 times then what will be its radius of orbit?

A satellite is orbiting the earth in a circular orbit of radius r. Its period of revolution varies as

The length of a simple pendulum is increased four times of its initial valuel, its time period with respect to its previous value will

The length of a simple pendulum is increased four times of its initial valuel, its time period with respect to its previous value will

The period of revolution of a satellite in an orbit of radius 2R is T. What will be its period of revolution in an orbit of radius 8R ?

The period of revolution of a satellite in an orbit of radius 2R is T. What will be its period of revolution in an orbit of radius 8R ?

If a time period of revolution of a satellite around a planet in a circular orbit of radius r is T,then the period of revolution around planet in a circular orbit of radius 3r will be

A satellite is revolving around a planet in an orbit of radius R. Suddenly radius of orbit becomes 1.02 R then what will be the percentage change in its time period of revolution?

Assertion: The time period of revolution of a satellite close to surface of earth is smaller then that revolving away from surface of earth. Reason: The square of time period of revolution of a satellite is directely proportioanl to cube of its orbital radius.