Thee lectron in the hydrogen atom circles around the proton with a speed of `2.18 xx 10^(6)ms^(-1)` in an orbit of radius `5.3 xx 10^(-11)m`. What magnetic field does it produce at the proton ?

The electron in the hydrogen atom circles around the proton with a speed of 2.18 xx 10^(6)ms^(-1) in an orbit of radius 5.3 xx 10^(-11)m . What magnetic field does it produce at the proton ?

The electron in a hydrogen atom circles around the positive nucleus with a speed of 2.18 xx 10^6 m//s in an orbit of radius 5.3 x 10^-11 m . Calculate the:- Magnetic field produced at the proton. Given e = 1.6 xx 10^-19 c , mu_0 = 471 xx 10^-7 Wb//Am

An electron in the hydrogen atom circles around the proton with a speed of 2.18xx10^(6) m/s in an orbit of radius 0.53Å . The equivalent current is

The electron in a H_(2) atom circles around the proton with a speed of 2.18 xx 10^(6) ms^(-1) in an orbit of radius 5.3 xx 10^(-11)m . Calculate (i) the equivalent current (ii) magnetic field produced at the proton.

The electron in a hydrogen atom circles around the proton with a speed of 2*18xx10^6ms^-1 in an orbit of radius 5*3xx10^-11m . Calcualte (a) the equivalent current (b) magnetic field produced at the proton. Given charge on electron 1*6xx10^-19C and mu_0=4pixx10^-7TmA^-1 .