In the figure, `/_ PQR` and `/_ PSR` are inscribed in the same are PQR and they intercept same are PR. If `/_ PQR = 65^(@)` then find the measure of `/_ PSR`

In the figure, /_PQR = 85^(@) then find the measure of /_ PTR .

In the figure, /_\PQR and /_\SQR are two triangles on the same base QR. If PS intersects QR at ‘O’, then /_\PQR:/_\SQR=

S is the incentre of triangle PQR . If angle PSR = 125^@ , then the measure of angle PQR is:

Prove that, angles inscribed in the same arc are congruent /_PQR and /_PSR are inscribed in the same arc. Arc PXR is intercepted by the angles. To prove : /_PQR ~= /_PSR Proof : m /_ PQR = (1)/(2) m ( arc PXR ) …... square m /_ square = (1)/(2) m (arc PXR ) ....(2) square :. m /_ square = m /_ PSR ......[ From (1) and (2) ] :. /_PQR ~= /_ PSR ...(Angles equal in measure are congrument )

Prove that, angles inscribed in the same arc are congruent . Given : angle PQR and angle PSR are inscribed in the same arc PXR. PXR is intercepted by the angles. To prove : angle PQR ~= angle PSR Proof : m angle PQR =1/2 m (arc PXR) " "(I) square m angle .........=1/2 m(arc PXR) " "(II) therefore m angle ....... =m angle PSR " " (From I and II) therefore angle PQR ~= angle PSR " " ( Angles equal in measure are congruent )

In a parallelogram PQRS, if angleS=125^@ , find the measure of angleP .

In the figure, square PQRS is cyclic side PQ cong RQ, /_PSR=110^(@) , Find measure of /_PRQ

In ∆PQR of Fig. 6.32, PQ = PR. Find the measures of ∠Q and ∠R.

In te figure triangle PQR and triangle SQR are two triangles on the same base QR. If PS intersects QR at 'O' then triangle PQR : triangle SQR =