If the arithmetic means of two positive number a and b `(a gt b )` is twice their geometric mean, then find the ratio a: b

If the arithmetic mean of two positive number a and b (a gtb ) is twice their geometric mean then a : b is

If the arithmetic mean of two positive numbers a & b (a gt b) is twice their geometric mean , then a : b is

If the arithmetic mean of two numbers a and b, a>b>0 , is five times their geometric mean, then (a+b)/(a-b) is equal to:

If the arithmetic mean of two numbers a and b,a>b>0, is five xx their geometric mean,then (a+b)/(a-b) is equal to:

The arithmetic mean of two positive numbers a and b exceeds their geometric mean by (3)/(2) and the geometric mean exceeds their harmonic mean by (6)/(5) . If a+b=alpha and |a-b|=beta, then the value of (10beta)/(alpha) is equal to

The arithmetic mean of two positive numbers a and b exceeds their geometric mean by (3)/(2) and the geometric mean exceeds their harmonic mean by (6)/(5) . If a+b=alpha and |a-b|=beta, then the value of (10beta)/(alpha) is equal to

If the arithmetic mean between a and b equals n times their geometric mean, then find the ratio a : b.

Show that the arithmetic means of two positive numbers can never be less than their geometric mean. The arithmetic and geometric means of two positive numbers are 15 and 9 respectively. Find the numbers.

The arithmetic mean of two positive numbers a and b exceeds their geometric mean by 2 and the harmonic mean is one - fifth of the greater of a and b, such that alpha=a+b and beta=|a-b| , then the value of alpha+beta^(2) is equal to