The force does water exert on the base of a house tank of base area `1.5m^(2)` when it is filled with water up to a height of 1 m is `(g=10(m)/(s^(-2)))`

What force does water exert on the base of a tank of base area 1.5m^(2) when it is filled with water upto a height of 1m (rhoH_(2)o = 10^(3) kg//m^(3).P_(0) = 10^(5)Pa and g=10m//s^(2))

What is force on the base of a tank of base area 1.5m^(2) when it is filled with water upto a height of 1m (rho_("water")=10^(3)kg//m^(3),P_(0)=10^(5)Pa and g=10m//s^(2))

A water tank is 13 m long, 14 m wide and 10 m deep. It is filled with water to a level of 5 m, what part of the tank is empty?

A tank of height 5m is full of water. There is a hole of cross-sectional area 1cm^(2) at its bottom. The volume of water that will come out from this hole per second is (g=10m//s^(2))

The power of a water pump is 2 kW. If g = 10 m//s^2, the amount of water it can raise in 1 min to a height of 10 m is :

The power of a water pump is 2 kW. If g = 10 m//s^2, the amount of water it can raise in 1 min to a height of 10 m is :

The level of water in a tank is 5m high.A hole of area 1cm^2 is made in the bottom of the tank. The rate of leakage of water from the hole is (g=10ms^(-2)