`x+iy=1/(1+costheta+isintheta),"then "4x^2=`

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|1+costheta+isintheta|=

(1+costheta-isintheta)^4 =

(1+costheta-isintheta)^(n)

(1-costheta+isintheta)^8 =

(1-costheta+isintheta)^6 =

(1-costheta+isintheta)^(6)

Find (costheta+isintheta)^n

If x+iy=3/(2+costheta +i sin theta) , then show that x^2+y^2=4x-3

If x+iy=(1)/(1+ cos theta+ isin theta) , show that 4x^(2)-1=0