If velocity (v) acceleration (A) and force (F) are three fundamental quantities in a system then what will be the dimension of linear momentum in this system?

Young's modulus is Y = stress /strain. Here stress is the force of reaction per unit area and strain is the change of length per unit initial length. Find out dimension of Y. If velocity (V) acceleration (A) and force (F) are taken as the fundamental quantities in place of mass length and time then what will be the dimension of Y ?

If velocity (v), acceleration (a) and force (F) are taken as fundamental quantities, the dimensions of Young's modulus (Y) would be

If velocity v acceleration A and force F are chosen as fundamental quantities, then the dimensional formula of angular momentum is terms of v,A and F would be

If velocity v acceleration A and force F are chosen as fundamental quantities, then the dimensional formula of angular momentum is terms of v,A and F would be

If the velocity (V), acceleration (A) and force (F) are taken as fundamental quantities instead of mass (M), length (L) and time (T), the dimensions of young's modulus (Y) would be :

Suppose you design your system of dimensions and take velocity (V), planck constant (h) and gravtitational constant (G) as the fundamental quantities. What will be the dimensions of length (L) in this system ?

Assuming velocity (V) time (T) and force (F) as the fundamental quantities find the dimension of density.