A particle is moving with velocity `v=4t^(3)+3 t^(2)-1 m//s`.
The displacement of particle in time `t=1 s` to `t=2 s` will be

A particle is moving with a velocity of v=(3+ 6t +9t^2) m/s . Find out (a) the acceleration of the particle at t=3 s. (b) the displacement of the particle in the interval t=5s to t=8 s.

A particle is moving with a velocity of v=(3+ 6t +9t^2) m/s. Find out (a) the acceleration of the particle at t=3 s. (b) the displacement of the particle in the interval t=5s to t=8 s.

If displacements of a particle varies with time t as s = 1/t^(2) , then.

A particle is moving with initial velocity 1m/s and acceleration a=(4t+3)m/s^(2) . Find velocity of particle at t=2sec .

Velocity of a particle is given as v = (2t^(2) - 3)m//s . The acceleration of particle at t = 3s will be :

Velocity of a particle is given as v = (2t^(2) - 3)m//s . The acceleration of particle at t = 3s will be :

The acceleration of particle varies with time as shown. (a) Find an expression for velocity in terms of t. (b) Calculate the displacement of the particle in the interval from t = 2 s to t = 4 s. Assume that v = 0 at t = 0.

The acceleration of particle varies with time as shown. (a) Find an expression for velocity in terms of t. (b) Calculate the displacement of the particle in the interval from t = 2 s to t = 4 s. Assume that v = 0 at t = 0.

Velocity-time equation of a particle moving in a straight line is, v=(10+2t+3t^2) (SI units) Find (a) displacement of particle from the mean position at time t=1s, if it is given that displacement is 20m at time t=0 . (b) acceleration-time equation.

Velocity-time equation of a particle moving in a straight line is, v=(10+2t+3t^2) (SI units) Find (a) displacement of particle from the mean position at time t=1s, if it is given that displacement is 20m at time t=0 . (b) acceleration-time equation.